pH = -log10(Ka) - log10([HA]/[A-])= 4.20 - log10([HA]/[A-])
in which
and
So pH = 4.20 - log10([2.5]/[1.8]) = 4.20 - log10(1.39) = 4.20 - 0.14 = 4.06
When sodium benzoate is acidified with H2SO4, it reacts to form benzoic acid. This reaction involves protonation of the benzoate ion by the sulfuric acid, leading to the creation of benzoic acid. The equation can be represented as: C6H5COONa + H2SO4 -> C6H5COOH + NaHSO4
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
There can be no such reaction. Perhaps you meant HCl(aq) + C6H5COONa to get C6H5COOH plus NaCl. That would be converting the sodium salt of benzoic acid (sodium benzoate) into benzoic acid and sodium chloride by using hydrochloric acid.
weak acid.
When benzoic acid reacts with barium hydroxide, it forms benzoate ions and barium benzoate. The balanced chemical equation for this reaction is: C6H5COOH + Ba(OH)2 → Ba(C6H5COO)2 + H2O. This is a double displacement reaction where the ions in the reactants switch partners to form new compounds.
Sodium Benzoic Acid
At the equivalence point, the moles of NaOH added will equal the moles of benzoic acid initially present in the sample. Since benzoic acid is a weak acid, it will partially dissociate in solution to produce benzoate ions and protons. At the equivalence point, all the benzoic acid has been converted to benzoate ions, resulting in a buffer solution of benzoate and its conjugate base. To calculate the pH at the equivalence point, you can use the Henderson-Hasselbalch equation, which considers the concentration of benzoate ions and benzoic acid to determine the pH of the solution.
NaC6H5COO is the chemical formula for sodium benzoate. It is a salt derived from benzoic acid that is commonly used as a preservative in food and beverages. Sodium benzoate helps inhibit the growth of bacteria, yeasts, and molds, prolonging the shelf life of products.
When sodium benzoate is acidified with H2SO4, it reacts to form benzoic acid. This reaction involves protonation of the benzoate ion by the sulfuric acid, leading to the creation of benzoic acid. The equation can be represented as: C6H5COONa + H2SO4 -> C6H5COOH + NaHSO4
C6H5COOH + NaHCO3 ===> C6H5COO-Na+ + H2O + CO2
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
K2CO3 + 2 benzoic acid -> 2 potassium benzoate + H2CO3
There can be no such reaction. Perhaps you meant HCl(aq) + C6H5COONa to get C6H5COOH plus NaCl. That would be converting the sodium salt of benzoic acid (sodium benzoate) into benzoic acid and sodium chloride by using hydrochloric acid.
weak acid.
When benzoic acid reacts with barium hydroxide, it forms benzoate ions and barium benzoate. The balanced chemical equation for this reaction is: C6H5COOH + Ba(OH)2 → Ba(C6H5COO)2 + H2O. This is a double displacement reaction where the ions in the reactants switch partners to form new compounds.
You're starting with something like sodium benzoate (depends on what base you used for the extraction step), which contains sodium ions (Na+) and benzoate ions (C6H5COO-). Ionic compounds like that tend to be soluble in water. When you add H+, you protonate the benzoate ion to make benzoic acid (C6H5COOH), which is a neutral molecule, and hardly soluble in water at all... so it precipitates.
Benzoic acid