C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
NaOH + HNO3 -> NaNO3 + H2O
On heating with sodalime (NaOH/CaO solid mix) carboxylic acids lose their -COOH group and produce a small alkane plus sodium carbonate: CH3CH2COOH + 2 NaOH →CH3CH3 + Na2CO3 + H2O Note how a carbon is lost from the main chain. The product of the reaction may be easier to identify than the original acid, helping us to find the structure. from Wiki
There can be no such reaction. Perhaps you meant HCl(aq) + C6H5COONa to get C6H5COOH plus NaCl. That would be converting the sodium salt of benzoic acid (sodium benzoate) into benzoic acid and sodium chloride by using hydrochloric acid.
Benzoic acid has a chemical formula of PhCOOH. It does not react with water so much as it dissociates in it, forming a free hydrogen ion. The reaction for the dissociation is PhCOOH(aq) --> PhCOO-(aq) + H+ (aq).
HCl+NaOH, when mixed in equimolar amounts, produces a neutral solution of NaCl.
NaOH + HNO3 -> NaNO3 + H2O
The reaction for benzoic acid and methyl amine produces benzamide. The equation is C6H5COOH + CH3NH2 ---> C6H5CONHCH3 + H2O.
There can be no such reaction. Perhaps you meant HCl(aq) + C6H5COONa to get C6H5COOH plus NaCl. That would be converting the sodium salt of benzoic acid (sodium benzoate) into benzoic acid and sodium chloride by using hydrochloric acid.
On heating with sodalime (NaOH/CaO solid mix) carboxylic acids lose their -COOH group and produce a small alkane plus sodium carbonate: CH3CH2COOH + 2 NaOH →CH3CH3 + Na2CO3 + H2O Note how a carbon is lost from the main chain. The product of the reaction may be easier to identify than the original acid, helping us to find the structure. from Wiki
Benzoic acid has a chemical formula of PhCOOH. It does not react with water so much as it dissociates in it, forming a free hydrogen ion. The reaction for the dissociation is PhCOOH(aq) --> PhCOO-(aq) + H+ (aq).
alkaline because in NaOH, Na is plus and OH is minus. when hydrogen is plus it is an acid when it is negative it is a base (alkaline)
HCl+NaOH, when mixed in equimolar amounts, produces a neutral solution of NaCl.
HCl + NaOH --> NaCl +H2O
An acid-base reaction
Sodium react with water:2 Na + 2 H2O = 2 NaOH + H2and2 NaOH + CO2 = Na2CO3 + H2O
An acid-base reaction yielding a salt and water.
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.