The reaction is the following:
Mg(OH)2 + 2 C6H5COOH = Mg(C6H5COO)2 + 2 H2O
I prefer Benzoic acid.
:)
benzoic acid + Sodium Hydroxide ==> water + sodium benzoate
Barium fluoride
The barium ion in barium hydroxide and sulfate ion in sulfuric acid combine to form barium sulfate, which is insoluble in water.
Barium hydroxide, Ba(OH)2, is a base.
yes.
benzoic acid + Sodium Hydroxide ==> water + sodium benzoate
Barium fluoride
The barium ion in barium hydroxide and sulfate ion in sulfuric acid combine to form barium sulfate, which is insoluble in water.
Barium hydroxide, Ba(OH)2, is a base.
yes.
just neutralized the benzoic acid by sodium hydroxide.....
Ba(OH)2 + H2SO4 ---> BaSO4 + 2H2O So one molecule of sulphuric acid will be neutralized by one molecule of barium hydroxide. Or two molecules of sulphuric acid will be neutralized by two molecules of barium hydroxide.
Barium sulfate is the precipitate
HCl + NaOH = H2O + NaCl Or, water and table salt--which will dissolve in water. Benzoic acid, C6H5COOH, will not be formed; neither of the two starting chemicals contains carbon, and benzoic acid contains a lot of it. - - - - - Benzoic acid and sodium chloride
Barium hydroxide is a base.
penis
Ba is Barium, OH is Hydroxide and the 8 H2O is Octahydrate. This results in Barium Hydroxide Octahydrate.