White precipitate will formed which is barium sulfate.
2Al(OH)3 + 3H2SO4 -> Al2(SO4)3 + 6H2O Looks like aluminum hydroxide and sulfuric acid will form the salt aluminum sulfate and water.
When barium hydroxide solution is mixed with sulfuric acid, a white precipitate of barium sulfate is formed due to a double displacement reaction. Barium sulfate is insoluble in water and thus forms a solid precipitate. This reaction is used in chemistry labs to test for the presence of sulfate ions.
Sulfuric acid reacts easily with sodium hydroxide to form sodium sulfate and water because sulfuric acid is a strong acid and sodium hydroxide is a strong base. This reaction occurs because both acids and bases react to form water and a salt. Hydrochloric acid may not react in the same way because it is a weaker acid compared to sulfuric acid.
Sulfuric acid cannot be used in place of hydrochloric acid in the barium chloride test because sulfuric acid would react with barium chloride to form insoluble barium sulfate. This would interfere with the precipitation reaction used to detect the presence of sulfates in the sample. Hydrochloric acid is preferred because it does not interfere with this reaction.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
2Al(OH)3 + 3H2SO4 -> Al2(SO4)3 + 6H2O Looks like aluminum hydroxide and sulfuric acid will form the salt aluminum sulfate and water.
Barium sulfate is the precipitate
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
When barium hydroxide solution is mixed with sulfuric acid, a white precipitate of barium sulfate is formed due to a double displacement reaction. Barium sulfate is insoluble in water and thus forms a solid precipitate. This reaction is used in chemistry labs to test for the presence of sulfate ions.
Ba(OH)2 + H2SO4 ---> BaSO4 + 2H2O So one molecule of sulphuric acid will be neutralized by one molecule of barium hydroxide. Or two molecules of sulphuric acid will be neutralized by two molecules of barium hydroxide.
Sulfuric acid reacts easily with sodium hydroxide to form sodium sulfate and water because sulfuric acid is a strong acid and sodium hydroxide is a strong base. This reaction occurs because both acids and bases react to form water and a salt. Hydrochloric acid may not react in the same way because it is a weaker acid compared to sulfuric acid.
This base is zinc hydroxide.
Sulfuric acid cannot be used in place of hydrochloric acid in the barium chloride test because sulfuric acid would react with barium chloride to form insoluble barium sulfate. This would interfere with the precipitation reaction used to detect the presence of sulfates in the sample. Hydrochloric acid is preferred because it does not interfere with this reaction.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
sulphuric acid+lithium hydroxide=lithium sulphate+water
sulphuric acid
It makes sodiumchloride and water