The 8088 brings in data in 8 bit chunks form the memory and must bring in two because internally it is 16 bit. The 8086 brings in the full 16 bits at one time. so it is the path to memory that differs.
The 8086/8088 microprocessor family is a 16 bit microprocessor. The 8086 implementation also has a 16 bit data bus, but the 8088 implementation has an 8 bit data bus, comparable to the 8085. The 8088 implementation was intended as a logical upgrade from the 8085, while keeping the complexity of the system on an equal footing as the 8085.
The highest memory address in the 8086/8088 is FFFFFH.
The 8088 is slower than the 8086 because the 8088 is running an 8-bit bus, while the 8086 runs a 16-bit bus. The two processors are the same, 16-bit processors, but the 8088 requires twice as many memory accesses to do the same amount of work as the 8086.
Memory to memory access is certainly possible in the 8086/8088 microprocessor. Look at the repeated string copy instructions.
The 8086/8088 is a 16 bit computer running on a 20 bit address bus. Processes use a segmented memory architecture to access one of four 64kb memory segments from a physical space of 1mb.
The 8086/8088 family of microprocessors was introduced by Intel.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
The 8086/8088 is the general purpose processor. The 8087 is the math co-processor for the 8086/8088.
1978 - 8086 1979 - 8088 First IBM PC used 8088. I think later low end IBM PC's used 8086.
The Intel 8086 and 8088 motherboards had the system bus speed, which is 5-10 MHz However, the processors for the motherboards had different external data bus widths with the 8088 CPU featuring an 8-bit bus and the 8086 a 16-bit bus.
You need some kind of memory expander, which maps a frame of addresses to a location in physical memory. Better, use an 8086/8088.