What is a sprinkler's "K-factor The K-factor is the nozzles's / sprinkler's constant at a given volume flow rate and is generally calculated with a formula: K = Q / √ p K = sprinkler's / nozzle's constant
Q = volume flow rate (l/min)
p = pressure at the sprinkler / nozzle (bar) examples: K-factor 57 = 171 l/min / √ 10 bar
K-factor 80 = 240 l/min / √ 9 bar
K-factor 115 = 345 l/min / √ 9 bar Generally the thread (DN) is associated with a K-factor. 3/8″ DN 10 K-factor 57
½″ DN 15 K-factor 80
½″ DN 15 K-factor 115
¾″ DN 20 K-factor 160 == ==
What is a sprinkler's "K-factor The K-factor is the nozzles's / sprinkler's constant at a given volume flow rate and is generally calculated with a formula: K = Q / √ p K = sprinkler's / nozzle's constantQ = volume flow rate (l/min)p = pressure at the sprinkler / nozzle (bar) examples: K-factor 57 = 171 l/min / √ 10 barK-factor 80 = 240 l/min / √ 9 barK-factor 115 = 345 l/min / √ 9 bar Generally the thread (DN) is associated with a K-factor. 3/8″ DN 10 K-factor 57½″ DN 15 K-factor 80½″ DN 15 K-factor 115¾″ DN 20 K-factor 160 == ==
Rasco 1993 H - K 14.2
Depends on the available pressure If you have 60 PSI coming into a structure then you will get 60 PSI out of the sprinkler Just look at the "K" factoring for friction losses
R. K. Sivanappan has written: 'Sprinkler irrigation' -- subject(s): Sprinkler irrigation, Sprinklers
The duration of The K Factor is 300.0 seconds.
The K Factor was created on 2010-02-06.
The K Factor ended on 2010-03-20.
It is a factor in all numbers of the form 310*k where k is an integer.
YES.If k is even then 2 is a factor of k.If 5 is also a factor of k then 2 x 5 = 10 is another factor of k.NOTE : The product of two or more prime factors of a number produces another factor.
k(k + 5)
If you have already determined whether your particular model is direct or inverse variation, then the two models will follow the following functions: Direct: y=kx ---y is always expressible as a constant multiple of x, meaning it varies directly with x by a factor of k Inverse: y=k/x ---y is always expressible as a constant multiple of the inverse of x (1/x). It varies directly with the inverse of x by a factor of k.
K-factor is a weighting of the harmonic load currents according to their effects on transformer heating, as derived from ANSI/IEEE C57.110. A K-factor of 1.0 indicates a linear load (no harmonics). The higher the K-factor, the greater the harmonic heating effects.