B and C
Whether a substance will precipitate can be determined if the ion product is compared to the solubility product constant. The value of any given equilibrium constant is accurate only at a specific temperature.
the product of 10p (p–q) is 10p²-10pq Given: 10p (p–q) To find : the product of 10p (p–q) Solution: we have to find the product of 10p (p–q). so product of any number means the multiplication multiply (p–q). by 10p we get, =10p× (p–q) =10p×p-10p× q =10p²-10pq the product of 10p (p–q) is 10p²-10pq
To determine if a precipitate will form from a given Ksp value, compare the ion product (Q) to the Ksp value. If Q is greater than Ksp, a precipitate will form. If Q is less than Ksp, no precipitate will form.
ion kon
The product of a hydronium ion (H3O+) and a hydroxide ion (OH-) is water (H2O). The hydronium ion and hydroxide ion react to form water in an acid-base neutralization reaction.
The resistance to an ion's movement across a membrane is primarily determined by the membrane's permeability to that specific ion. Factors such as ion channel proteins, membrane potential, and concentration gradients also play a role in regulating ion movement.
H+(aq) and OH-(aq) hydrogen ion and hydroxide ion
The product is neutral.
Element Q is oxygen, with an atomic number of 8. Since the ion Q2 contains 10 electrons, it has gained 2 electrons, making it a negatively charged ion.
The relationship is that the product of the ion concentrations must equal the Ksp value for the solution to be saturated. If the product exceeds the Ksp value, then a precipitation reaction will occur until equilibrium is reached. Conversely, if the product is less than the Ksp value, the solution is not saturated and more solute can dissolve.
The product of the H3O+ ion concentration and the OH- ion concentration in water is always equal to the ion product of water, which is 1.0 x 10^-14 at 25°C. This relationship is described by the equation [H3O+][OH-] = 1.0 x 10^-14.
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