a few years
noyhing but test - positive control
It is my first answer. Is the problem to solve A=B^X ? where A and B are positive integers and X the power exponent of B The given equation can be rewritten in a logarithm form. Log A = X * Log B solving for a unique X X = Log A / Log B The result: Any positive integer A can be rewritten as a positive integer B to the distinct power X. Where X is Log A divided by Log B A = B ^(Log A / Log B) I think, this is the solution. Roger Verbeeck
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Logs are defined only for positive numbers so the log of a negative number does not exist.
Log(y) can be any number, positive or negative, no limits. It all depends on the value of 'y'.
There is no answer - it is an error: negative numbers do not have logarithms. The log if a number tells to what power the (positive) base must be raised to get the number. Raising any positive number to any power will never result in a negative number, so it is an error to try and take the log of a negative number.
"Log" is short for "logarithm, a quantity representing the power to which a fixed number (the base) must be raised to produce a given number.
2 log(x) = log(8)log(x2) = log(8)x2 = 8x = sqrt(8) = 2.82843 (rounded)Note that only the positive square root of 8 can serve as a solution to thegiven equation, since there's no such thing as the log of a negative number.
No. log 20 is a positive number , so it you subtract it from log 5 you get less than log 5. However, log10 5 = 1 - log102 = 2- log1020 . or log 5 - log 20 = log 5 - log 4*5 = log 5 - (log 5 + log 4) = log 5 - log 5 - log 4 = - log 4 But we do not need to do all of these computations, because log 5 is different from log 5 - log 20 by the law of the equality that says two equals remain equal if and only if we subtract (in our case) the same thing from them.
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Log on then click on renassance place when it loads click on pupil (or teacher) and log on, after that click on take a quiz then log on to your english teachers name and click take a reading practise test. THen click on read indipendantly (if is the case) and and then tipe in the code or title of the book and find the book you have just read. 'when it says are you sure you want to take this test click on yes then you will start the test