If it's a superconductor, it can be arbitrarily long.
If it's not, then if it's any length at all, there will be a voltage drop. It may be small for short distances of thick wire, but there will be some.
Line-voltage thermostats are typically used with electric baseboard heaters.
To find the line voltage at the panel, you need to add the voltage loss to the voltage at the receptacle. Since the receptacle has 110 V and there is a voltage loss of 6 V, the line voltage at the panel is 110 V + 6 V = 116 V.
The recommended thermostat for an electric baseboard heater is a line-voltage thermostat designed specifically for use with electric heating systems.
There is normally no voltage on the neutral line because the neutral line is grounded. However, and this is always important, do not assume that neutral is grounded, nor that there is not an elevated voltage on neutral or ground due to a possible ground fault.
If the phase voltage is 230 V, then (providing you are describing a three-phase, four-wire, system), then the line voltage will be 1.732 larger -i.e. 400 V.
The line current increases when more bulbs are switched on in parallel, since more parallel current paths results in lower effective resistance. The line voltage should not change in response to any normal use of electric power in a single house.
Pacific DC Intertie, a 500KV direct-current power line from The Dalles, Oregon to Los Angeles.
Line-to-line voltage in a three-phase system is calculated using the formula ( V_{LL} = \sqrt{3} \times V_{LN} ), where ( V_{LN} ) is the line-to-neutral voltage. This relationship arises because the line-to-line voltage represents the voltage difference between two phases, while the line-to-neutral voltage is the voltage from a phase to the neutral point. If you have the line-to-line voltages directly measured, you can also use the voltage differences between any two phases to determine the line-to-line voltage.
A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line. A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line.
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
To convert a 440V line voltage to phase voltage in a three-phase system, you divide the line voltage by the square root of 3 (approximately 1.732). This means the phase voltage is calculated as ( V_{phase} = \frac{V_{line}}{\sqrt{3}} ). For 440V line voltage, the phase voltage would be approximately 254V.
Phase, if you are referring to line, as power line from pole.