Zero time.
It would depend on the dominant gene: I would compare the mother's parents eyelashes to the father's parents eyelashes, for each of the parent's eyelashes that are long it is an increase in 25% that the offspring will have long eyelashes. Unless half of the father's parents have long lashes then that shows the short lash gene is dominant.
age of 21
Asexual: the offspring has a single parent.Sexual: the offspring has two parents (combining some chromosomes from each parent). In asexual reproduction, as long as there are no mutations, the offspring are identical to the parents; in sexual reproduction, they are not.
There have been few observations of aye-aye behavior in the wild, but they appear to have offspring every 2 to 3 years, so the offspring probably stay with their parents for about that long.
some of grasshopper live long at the forest and so on
it doesnt it doesnt
the long necks and what the parents have but sometimes the giraffes wont be the same as the parents
until there are well to leave at around 19-21
In 9-12 weeks the offspring will leave the parents and by the next summer the females will be sexually mature.
like 9 moths
The wing length of the F1 offspring will depend on the specific genetics of the parent organisms. It will be a combination of genetic factors from both parent organisms, following the principles of inheritance.
It's obvious from this problem that short hair is dominant in guinea pigs. In that case, if we have 25 out of 100 offspring that have long hair, then there is no doubt that the parents are heterozygous for short hair. If you use the punnet square, and hypothesize that both parents are heterozygous for short hair and long hair, you will get a 25% chance that the offspring will be long haired. So, the answer to this problem is that both parents are heterozygous. Let H = short hair and h = long hair. Hh dam x Hh sire gives us, according to the Punnet Square: 25% HH 50% Hh 25% hh