18 Seconds (:
Divide 500 by 25. The answer is 20.
480 joules = 480 watt-seconds20 watts x (time) = 480 watt-secondsDivide each side by 20 watts:Time = 24 seconds
Power (Watts) is Joules (energy) per Second (time) so divide the number of joules by the number of seconds. 104/60 = 1.733 Watts
A watt is equal to 1 Joule per second. So 432 Joules * (1 / 75 Joules per second) = 432/75 = 5.76 seconds.
25 sec.
18 Seconds (:
Divide 500 by 25. The answer is 20.
480 joules = 480 watt-seconds20 watts x (time) = 480 watt-secondsDivide each side by 20 watts:Time = 24 seconds
Power (Watts) is Joules (energy) per Second (time) so divide the number of joules by the number of seconds. 104/60 = 1.733 Watts
A watt is equal to 1 Joule per second. So 432 Joules * (1 / 75 Joules per second) = 432/75 = 5.76 seconds.
Horsepower is a unit of power. 1 horsepower = 745.699872 watts The formula for Power is this: Power = Work/TimeThe SI unit of power is the watt (W), which is equal to one joule per second. The SI unit for work is the joule (J). The SI unit for time is seconds (s).
it will take more than100 watts until the filament reaches operating temperature so perhaps a second to get as low as 100 watts . then 100Watts there after until 300 hours pass then 0 watts if you mean 100Watt hours then the answer is 1 hour and the hour will cost about a penny
If you can stuff the 780 Joules of energy through the system in 0.0052 second,then the power during that time is780/0.0052 = 150,000 watts.But it only lasts for that 5.2 milliseconds, and then you're out of joules.
Energy is measured in Joules, not in Watts. Watts is a unit of power, and is equal to Joules / second. To calculate the potential energy (in Joules), convert the units to SI units (lbs to kilograms, feet to meters), then use the formula potential energy = mass x gravity x height. Use 9.8 meters per second square for gravity. A2: The Energy to lift 1000 # 10 feet is 10kft# or 40/3 k Joules.
15 watts
They come in different sizes, and power ratings. Look at your dryer; somewhere it should have electrical specifications. These should either include a power (in watts), or volts and amperes separately. If volts and amperes are listed separately, multiplying them gives you a good idea of the amount of watts consumed. Note: watt is a unit of power, not of energy. You need to multiply that by the time you use the device, to get energy: joules = watts x seconds