The diagonal is 47.707'
The diagonal is 100'
156.2 units.
The diagonal is 221.2 inches long.
26.4 inches for the diagonal.
157.6102789 inches
152feet 3.79inches (rounded)
20 ft
134.6 feet
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
By Pythagoras, the length of the diagonal = sqrt[(1.8)2 + (1.2)2] = sqrt[3.24 + 1.44] = sqrt[4.68] = 2.16 m
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft