>I=Prt
> 300=1000(0.03)t
> t=10
Time duration will be 10 years.
1 year
Kate invested 4500.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
Two equations. x+y=56000 .07x=.05y Solve both of these equations simultaneously and it will be the answer. x+(.07/.05 x)=56000
A $5000 investment at an annual simple interest rate of 4.4% earned as much interest after one year as another investment in an account that earned 5.5% annual simple interest. How much was invested at 5.5%?
an investmntment of 4000 is made at an annual simple interest rate of 8%. How much additional money must be invested at 12% so that the total interest earned is 1640?
72
Take the annual interest rate, divide it by 2 and multiply it by the amount you invested or borrowed.
Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70
20, assuming annual compound interest, 24 if simple interest.
99999999.99999
300 :D
500 principal, 10 percent annual rate => 50 annual interest 2 year => 100 total interest.