by the laws of motion(s=ut+gt2) you can easily find out the answer, where s is the height, u is the initial velocity(in this case its 0), g is the acceleration due to gravity. since u is 0 the equation reduces to s=gt2 the answer is about 3.1 sec
The acceleration a of an object falling at the surface of the earth is 9.81 m/s^2 (or 32 feet/s^2). So its velocity v is acceleration times falling time t.
v = a * t
And its distance travelled (or height fallen) is
s(t) = -1/2 * a * t^2 + v*t + h
Where s is position, a is acceleration, t is time, v is initial velocity (when t = 0), and h is initial height (when t = 0). Using the figures given above for a, this function will consider ground to be 0, and up to be the positive direction.
One more useful equation is Vf²=Vi² + 2*a*x
Where Vf is final velocity, Vi is initial velocity, a is acceleration, and x is change in position (displacement, or the distance travelled in a straight line).
Using the last equation to answer your question:
Vf² = 0² + 2 * 32 * 100 = 6400
Vf = sqrt(6400) = 80
So, the rock would be travelling at 80 feet per second at the instant before it hits the ground. (Obviously, once it hits the ground it will be stopped). This assumes that the rock started from rest.
Note that air resistance is not taken into consideration. The equations become significantly more complex when drag is introduced, and more information about the rock than is given would be required.
As an object falls, its speed keeps growing, and it takes less and less time to cover each
100 feet. The first 100 feet, after the object is dropped, is covered in about 2.5 seconds.
300 feet, or the length of a football field.
Height in meters 100
4.5 seconds.
5 seconds
that depends on which airplane you're talking about.
Surely you're aware that a falling object accelerates under the influence of gravity. That acceleration manifests itself in the form of steadily-increasing speed, so the time required to fall 186 feet depends on how long it has already been falling. -- Immediately after it's dropped, the object falls the first 186 feet in 3.399 seconds. -- It falls the NEXT 186 feet in 1.408 seconds. -- It falls the next 186 feet in 1.08 seconds. -- It falls the next 186 feet in 0.911 second. -- It falls the next 186 feet in 0.802 second. . . etc.
THE MOON IS PURPLE
Yes. Because paper is much much lighter than a bowling ball so if you drop them the paper will take atleast 1.3 seconds to fall and a bowling ball will take atleast 0.5 seconds.
2.666666667 seconds
8 seconds
4 seconds
depends on weight of object and wind strength.normally heavy objects will drop down faster than lighter objects.
-- Take a heavy object and a stopwatch. -- Start the timer as you drop the object from the unknown height. -- Stop the timer when the object hits the ground. -- Read the time off the watch, in seconds. Square it. (Multiply it by itself.) -- Multiply that result by 16.1 . -- Now you have the distance the object fell, in feet.
5 seconds
It depends on what height you drop it from.
Take an amount of water of which you know the volume. Drop the object in the water. Find the difference
Based on your question alone, it is impossible to tell how many millennia it would take for an object "like this" to be buried 300 feet in the ground. We cannot see the object to which you are referring.
[object Object]
[object Object]
If it breaks on impact, it would be almost instantaneously.