5.00 kg of Cu is equivalent to 78,68 moles.
First we need to know the density of that material. Eg the density of 20mm is 1528 kg/cum : 1528/35.28 = 43.31 kg/cft. Lets asume that wee have 500 kg 20 mm. So 20mm (kg to cft) 500/1528 = 0.327 cum(multiply by 35.28 becoz it is in cum) 0.327*35.28 = 11.53 Cu ft. So 500 kg of 20mm = 11.53 cu ft
1 kg of difluorodichloromethane is equivalent to 8,27 moles.
12,4439 kg of gold contain 63,177 moles.
The numbers of moles in 100 kg of sodium is 4 349,76.
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
First we need to know the density of that material. Eg the density of 20mm is 1528 kg/cum : 1528/35.28 = 43.31 kg/cft. Lets asume that wee have 500 kg 20 mm. So 20mm (kg to cft) 500/1528 = 0.327 cum(multiply by 35.28 becoz it is in cum) 0.327*35.28 = 11.53 Cu ft. So 500 kg of 20mm = 11.53 cu ft
Take density of MS @ 7.85 grams / cubic centimetre Convert all dimensions to centimeters Volume = 5 * 1 *100 = 500 cu cms > 500 cu cms @ 7.85 gram cu cm = 500 * 7.85 = 3925 gram ( 3.925 kg)
0.5 kg = 500 g0.5 kg = 500 g0.5 kg = 500 g0.5 kg = 500 g0.5 kg = 500 g0.5 kg = 500 g
There is no conversion. "Cu ft" is a volume measurement, "kg" is a mass measurement.
1 kg of difluorodichloromethane is equivalent to 8,27 moles.
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
2.70 m = 2.70 moles/kg solvent3250 g solvent = 3.25 kg solvent2.70 moles/kg x 3.25 kg = 8.775 moles NaNO3 = 8.78 moles NaNO3 (3 significant figures)
There are 0.003528 lots of 500 kg in 1.764 kg.N of 500kg = ( 1.764 kg )/ ( 500 kg ) = 0.00353 500-kg in 1.764 kg
500 kg. k=1000 500x1000=500,000grams cmon man easy stuff.
The numbers of moles in 100 kg of sodium is 4 349,76.
12,4439 kg of gold contain 63,177 moles.
Aluminum: 2700 kg/cu. m Teak Wood: 630 - 720 kg/cu. m