The numbers of moles in 100 kg of sodium is 4 349,76.
To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
To find the gram molecular mass of the compound, you can use the formula: mass = moles × gram molecular mass. Given that 5 moles of the compound have a mass of 100 grams, you can rearrange the formula to find the gram molecular mass: gram molecular mass = mass / moles. Thus, gram molecular mass = 100 grams / 5 moles = 20 grams per mole.
100/150.158 is 0.666 moles
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
There would be 0.75 moles in 1 liter of solution. You have 100 mL which is in fact 0.1 liters. so you would have 0.1 of 0.75 moles. 0.1 x 0.75 = 0.075 moles.
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
Your equation is properly balanced so for every mole of hydrogen produced it takes 2moles of sodium; therefore to produce 4.0 mol of hydrogen it would take at least 8.0 mol of sodium if the reaction were 100 % efficient.
To calculate the mass of 2.5 moles of sodium hydroxide (NaOH), you need to know the molar mass of NaOH, which is 40 g/mol. Multiply the number of moles by the molar mass: 2.5 moles x 40 g/mol = 100 grams of sodium hydroxide.
To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
The average is the sum of those 100 numbers divided by 100.
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
To find the gram molecular mass of the compound, you can use the formula: mass = moles × gram molecular mass. Given that 5 moles of the compound have a mass of 100 grams, you can rearrange the formula to find the gram molecular mass: gram molecular mass = mass / moles. Thus, gram molecular mass = 100 grams / 5 moles = 20 grams per mole.
100/150.158 is 0.666 moles
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
Ah, isn't that a lovely question? To find the number of moles in 100 g of MgCO3, we first need to know the molar mass of magnesium carbonate (MgCO3). Then, we can use the formula: moles = mass / molar mass. Just like painting a happy little tree, it's all about following the steps and enjoying the journey to the answer.
0 and 100.
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.