To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
100 grams is 3.527 ounces.
100 g = 3.527 oz
One Canadian toonie weighs approximately 7.3 grams. To find out how many toonies would weigh 100 grams, you would divide 100 grams by 7.3 grams to get approximately 13.7 toonies.
Quinoa contains around 14 grams of protein in 100 grams of cooked quinoa.
100 grams of chocolate is approximately 3.5 ounces.
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
The density of argon at 100 degrees Celsius is approximately 1.784 grams per cubic centimeter.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
grams of mercury (Hg) 1 mole x 1 mole Avogadro's number (6.022 x 1023) of atoms 200.6 grams Hg 1 mole 200.6 grams Hg = x = ≈ 3.3311192-23 atoms Hg 1 mole 6.022 x 1023 atoms 6.022 x 1023 atoms
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
100 grams = 3.5 ounces.
100 grams is 3.527 ounces.
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
.1 Kg = 100 grams
Assume 100 grams and change those percents to grams. Get moles. 67 grams S (1 mole S/32.07 grams) = 2.089 moles S 33 grams O (1 mole O/16.0 grams O) = 2.063 Normally you would call the smaller mole number " 1 " and use it to divide the other mole number to get a whole number for the empirical formula, but these mole numbers are basically the same, so both are " 1. " SO Is the empirical formula
There are 1000 grams in a kilogram. One tenth of 1000 = 100 grams.
100 g = 3.527 oz