We assume 100 grams of compound and change % to grams. Get moles.
40 grams S (1 mole S/32.07 grams) = 1.247
60 grams O (1 mole O/16.0 grams) = 3.75
Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value.
3.75 mole O/1.247 mole S = 3.00
SO3
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is the empirical formula
Since the atomic mass of sulfur is very close to twice the atomic mass of oxygen, the ratio of numbers of oxygen atoms to numbers of oxygen atoms is close to 43:28.5. The closest ratio of small integers is 3:2; therefore the empirical formula is S2O3.
No, Compounds with the same empirical formula have the same elements in the same ratio. SO2 and CO2 contain different elements. SO2 is a compound of sulfur and oxygen while CO2 is a compound of carbon and oxygen.
The answer is Fe2O3
The chemical formula for Calcium oxide is CaO. A single calcium atom bonds with a single oxygen atom to make this compound, and a link can be found below for more information.CaO
We assume 100 grams total and turn those percentages into grams. Get moles elements. 29.6 grams O (1 mole O/16.0 grams) = 1.85 mole O 70.4 grams F (1 mole F/19.0 grams) = 3.71 mole F now divide both moles by smallest number to get mole ratio for empirical formula 1.85/1.85 = 1 for O 3.71/1.85 = 2 for F so the empirical formula for this compound is........ OF2
P2o5
p2o5
S2o3
MgO
CaSO4
One atom of carbon, two of oxygen.
Data:96.2% thallium.3.77% oxygen.The empirical formula is Tl2O.
As2O3
Since the atomic mass of sulfur is very close to twice the atomic mass of oxygen, the ratio of numbers of oxygen atoms to numbers of oxygen atoms is close to 43:28.5. The closest ratio of small integers is 3:2; therefore the empirical formula is S2O3.
SO3
We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.
C3h4o2