64
Sixty-four 2048 kilobyte files can be stored on a 128 megabyte flash drive. To find the answer, convert 128 mb to kb, which is 131072 kb, and divide that number by 2048 kb.
2MB = 2048kB2048kB/60kB per file = 34 files, with 8kB to spare.
This computer's memory type is: DDR2 SDRAM, with a hard drive capacity of 160GB (solid state disc flash memory). For further reference the cpu speed is 1.60 Hz and internal memory is 2048 MB.
4096
2048
211 = 2048.
We'll have to wait to 2048 to find out, unless you can see the future?
(2048 + 2035)/2 = 2041.5
2048 bytes 2048 bytes
'2' is the only prime factor . Reason 2^(11) = 2048 . Since '2' multiplied to itself eleven times over is 2048.
2048
It is 2 and 2 to the power of 11 = 2048