20 tablets are necessary.
Two
To make 50 ml of a solution with a concentration of 500 mg per 5 ml, you would need to calculate the total amount needed: 50 ml / 5 ml = 10 units of 5 ml that are needed. Since each unit of 5 ml requires 500 mg, you would need 10 units x 500 mg = 5000 mg. To find out how many 250 mg tablets are needed to make 5000 mg, you would divide 5000 mg by 250 mg per tablet, which equals 20 tablets needed.
The Bessemer process produced the lightweight steel needed to build a suspension bridge.
2 TABLETS
To prepare a DCPIP (2,6-dichlorophenol indophenol) solution from tablets, first dissolve the required number of DCPIP tablets in a small volume of distilled water, typically around 100 mL. Stir the mixture until the tablets are completely dissolved, ensuring there are no undissolved particles. Once fully dissolved, you can dilute the solution to the desired final concentration with more distilled water if needed. Store the solution in a dark bottle to protect it from light, as it can degrade over time.
To find the total amount of sodium fluoride needed, first convert 110 μg to grams (110 μg = 0.00011 g). Then multiply the amount per tablet by the number of tablets: 0.00011 g x 600000 = 66 grams of sodium fluoride are needed to make 600000 tablets.
Depending on the needed concentration of salt !
50mg ---> 5ml ?mg -----> 100ml Use the cross mutliplication method to find ? 50 x 100 / 5 = ? ? = 1000mg Answer is 2 x 500mg tablets
The Bessemer process produced the lightweight steel needed to build a suspension bridge.
Depending on the desired concentration of the solution !
lex tablets can be pound
To make a solution from one concentration to another, you can use the formula: C1V1 = C2V2. Here, C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. By rearranging the formula, you can calculate the volume of stock solution needed to achieve the desired concentration in a given volume.