You have 4 options for the first digit, 3 for the second, 2 for the third. Multiplying all this you get 4 x 3 x 2 = 24 options.
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From left to right, pick the smallest possible digit every time. This will give you the smallest possible number.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
20From Rafaelrz,The number of three digit permutations you can get from the four different digits3. 6. 7. 9, is given by:4P3 = 4!/(4-3)! = 4x3x2x1/1 = 24
It is difficult to interpret exactly what you are trying to ask. If you allow your five digit number to have leading zeroes and do not allow negative numbers, then 00000 - 99999 = -99999 is the smallest number. If you do allow negative 5 digit numbers, then (-99999) - 99999 = -199998 is the smallest number.
Nope, look at 1000, this is a 4 digit number and we can't list it with 1,2,3, and 4
3! = 6.
From left to right, pick the smallest possible digit every time. This will give you the smallest possible number.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
210
24680
There are 2 choices for every digit in the 6-digit number. So 26 is 2*2*2*2*2*2. The answer to that is 64.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
625×2=1250
1,023.
88,888
123478
998,000