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Let's consider the following distribution:

__ __ __

Each space represents one number.

The first number can be anything from 0-9 (10 possibilities).

The second number, after choosing the first number, can only have 9 possibilities. The reasoning behind this is if we choose the same number as the first, then there is a repetition. So we can't use that same number again.

The third number can only have 8 possibilities by the same logic as for the second digit.

Therefore there can be 10*9*8 = 720 3-digit numbers with no repetitions of digits.

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Q: How many 3 digit numbers contain no repetition of digits?
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