Assuming you can have duplicate letters such as AAA, AAB etc... there are 26 x 26 x 26 combinations - which is a total of 17,576 permutations !
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
6
120
233 = 18 combinations.
3 items each in 3 categories gives 3*3*3 = 27 possible combinations.
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
You did not give us the set to work with...
6
676,000 but I don’t know why
The letter 'W'.
120
17,576 possible combinations * * * * * Not quite! This is the total number of permutations of 3 letters out of 26. AAB is counted as being different from ABA or BAA. But these are the same combinations. Thus there are 26 combinations of just one letter. 26*25 combinations of two letters and 26*25*24/(3*2*1) of three. In all, that makes 26 + 650 + 2600 = 3276
Gematriya is a numerical version of the Hebrew alphabet. For example, the first letter of the Hebrew Alphabet is the letter Aleph. This letter's Gematriya translation is 1 then the second letter Bet=2 Gimel= 3 Daled=4 Hey=5 etc. except there are many letters that do not correspond to the number in the alphabet that it is.
ABC
There are: 35C3 = 6545 combinations