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How many 5 letter combinations can be made from the alphabet if 3 are consonants and 2 are vowels?
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
How many three-letter combinations can be made from 3 letters?
6
How many 3-letter code words are possible using the first 6 letters of the alphabet if no letter can be repeated?
120
How many three letter combinations can you make from 4 letters?
From 4 letters, you can create three-letter combinations by selecting any 3 letters from the 4 and arranging them. The number of ways to choose 3 letters from 4 is given by the combination formula ( \binom{4}{3} = 4 ). Each of these combinations can be arranged in ( 3! = 6 ) ways. Therefore, the total number of three-letter combinations is ( 4 \times 6 = 24 ).
How many combinations of three letters could there be?
The number of combinations of three letters depends on whether repetition is allowed and whether the order matters. If we assume there are 26 letters in the English alphabet and repetition is not allowed, the combinations can be calculated using the formula for combinations: ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ). For 26 letters and choosing 3, this results in ( \binom{26}{3} = 2,600 ) combinations. If repetition is allowed, the number of combinations would be ( 26^3 = 17,576 ).
How many 5 letter combinations can be made from the alphabet if 3 are consonants and 2 are vowels?
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
How many possible combinations of 3 letters can you make?
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
How many 3 letter combinations are there in license plates?
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
How many 3 letter combinations can be made from this set ABCDEFG if no letter can be repeated?
You did not give us the set to work with...
How many 3 letter combinations?
17,576 possible combinations * * * * * Not quite! This is the total number of permutations of 3 letters out of 26. AAB is counted as being different from ABA or BAA. But these are the same combinations. Thus there are 26 combinations of just one letter. 26*25 combinations of two letters and 26*25*24/(3*2*1) of three. In all, that makes 26 + 650 + 2600 = 3276
How many three-letter combinations can be made from 3 letters?
6
A keycode must contain 2 letters and 3 numbers. The letters may be any letter of the alphabet. The numbers should be any number from 0 to 9. How many different keycode combinations are there?
676,000 but I don’t know why
How many 3-letter code words are possible using the first 6 letters of the alphabet if no letter can be repeated?
120
What is the ONLY letter in the alphabet that has 3 Syllables?
The letter 'W'.
How many three letter combinations can you make from 4 letters?
From 4 letters, you can create three-letter combinations by selecting any 3 letters from the 4 and arranging them. The number of ways to choose 3 letters from 4 is given by the combination formula ( \binom{4}{3} = 4 ). Each of these combinations can be arranged in ( 3! = 6 ) ways. Therefore, the total number of three-letter combinations is ( 4 \times 6 = 24 ).
What is gematria?
Gematriya is a numerical version of the Hebrew alphabet. For example, the first letter of the Hebrew Alphabet is the letter Aleph. This letter's Gematriya translation is 1 then the second letter Bet=2 Gimel= 3 Daled=4 Hey=5 etc. except there are many letters that do not correspond to the number in the alphabet that it is.
How many combinations of three letters could there be?
The number of combinations of three letters depends on whether repetition is allowed and whether the order matters. If we assume there are 26 letters in the English alphabet and repetition is not allowed, the combinations can be calculated using the formula for combinations: ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ). For 26 letters and choosing 3, this results in ( \binom{26}{3} = 2,600 ) combinations. If repetition is allowed, the number of combinations would be ( 26^3 = 17,576 ).
