There are 6 solutions in all.
The middle digit must be 0 , 2 or 4.If the middle digit is 0, then the first two digits must sum to 3. There are three possible solutions: 12, 21 and 30.
If the middle digit is 2, then the first two digits must sum to 2. There are two possible solutions: 11 and 20.
If the middle digit is 4, then the first two digits must sum to 1. There is one possible solutions: 10.
10401
11211
12021
20202
21012
30003
35.
There are 10 3-digit odd palindromes that are divisible by five.
-4
90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.
There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
There are five such numbers.
There are 5460 five digit numbers with a digit sum of 22.
-1
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.
9
The smallest 5 digit integer is -99999. The largest 5 digit integer is 99999. The sum is therefore 0.
Zero.