If 12,000 btuh = 1 ton cooling = 2000 pounds ice; then 12 btuh will melt 2 pounds of ice to water.
sw Florida - none
Depends on the temperature of the water. If it is 32 degree water and you want 32 degree ice then you need a -144 BTU loss to change state from liquid to solid. It takes 1 BTU to raise the temperature of 1 pound of water 1 degree (F). If the water is 82 degrees then you would need a -50 BTU loss (+) 144 BTU to change state. TOTAL WEIGHT OF WATER (X) 1 BTU (X) Degrees desired of change. If it is ICE to WATER then it is the TEMP of ICE (X) .5 BTU (X) NUMBER OF DEGREES INCREASED = TOTAL BTU needs. If you change state in the process you have to add 144 BTU for 32 degree ICE to 32 degree WATER and 970 BTU for 212 degree WATER to 212 degree STEAM but only when you change state.
there are 100.000 btu's in a therm.
1 BTU = 1055 Joules
The answer: 17070 BTU The math: 3414 BTU = 1 KVA (KW) so 5 KVA = 17070 BTU
10 x (70 - 50) = 200 Btu
212-65=147. 147(20)=2940 btu needed is this right?
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
135 btu
32 BTU = 24,901.416 foot-pounds.
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
1 gallon of water weighs 8.34 pounds. It takes I BTU to change the temp of 1 pound of water 1 degree F. So for 1 gallon it takes 8.34 BTU. It takes 3412.14 BTU to equal 1 KWH. So 8.34 Btu x (1KWH / 3412.14 BTU) = 0.002444 KWH
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
The latent heat of vaporization of water at 212 degrees Fahrenheit at atmospheric pressure involving only vaporization and no saturation is 970 BTU/lb, so to evaporate 15 lbs of water we need 970 x 15 = 14550 BTU's
what is the answer to this
It takes 8.33 BTU to raise the temperature of water 1 degree F.
sw Florida - none