UK Mains is 230V therefore 6 KW is 6000/230 = 26 Amps.
3 phase is slightly different.......
6000/400V = 15 Amps/root 3 = 8.67 Amps per phase.
no
The most you could use would be 48 kW. P = E x I = 240 x 200 = 48,000 = 48 kW
What is the KW of 4 50 amp rectifiers at a 48 volt DC system
The equation that you are looking for is kW = Amps x Volts/1000. My average Sony audio amp at home uses about 20 watts or .02 kW at a low audio output level.
To calculate the power in kilowatts (kW) from amps (A), you also need the voltage (V). If the voltage is 120V, then 500A would equal 60 kW (since Power (kW) = Current (A) x Voltage (V) / 1000). However, without knowing the voltage, it's not possible to calculate the power in kilowatts.
To calculate the kilowatts (kW) when given voltage (V) and current (I), you can use the formula: kW = V x I x √3 / 1000 For 480V, the calculation would be based on the current flowing through the circuit.
No; drawing more than the rated amperage from a transformer will cause it to overheat.
It depends on what kind of amp it is. Is it an audio amp or an rf amp . . A 3 kW audio amp would draw about 300 watts on average at most, so with a good reservoir capacitor the supply current would be 0.2 amps. A 3 kW rf amp for AM radio would draw about 4500 watts so the supply current would be 3 amps.
1.341hp per kW
About 1.34hp per kW
There are 1,000 watts in a kilowatt (kW).
Look at the motor nameplate and it shoud have the amp draw on it. If the nameplate is missing, then the amp draw depends on what type of motor it is. The basic calculation to get you in the ball park would be as follows: 1 HP = 0.75 KW 7.5 HP = 5.63 KW Assume the efficiency of the motor is 80%, then the power supplied will need to be 5.63/0.8 = 7.04 KW amp draw = 7040/220 = 32 amps <<>> For calculation purposes the electrical code book states that a 7.5 HP motor draws 40 amps.