First we convert horsepower to watts. 1 Horsepower equals 745.7 watts. Next, using the Ohm's law formula P=IxE where P is power measured in watts; I is current measured in amps; E is voltage measured in volts.
Therefore
5(745.7) / 240 = 15.5 amps
<<>> The current taken by a motor is highly variable depending on efficiency, power factor and the mechanical load. On a 240 v system you should allow 7 amps per HP. So for 5 HP you should allow 35 amps.
Since 2-phase systems went out of use 100 years ago you probably have a single-phase motor which has two suppy wires, a live and a neutral, plus probably an earth wire.
The 5 horsepower is its output power, so it depends on its efficiency. Once you know that, you can determine its input power and then use the equation:
P = 1.732 EL IL
to determine the line current (IL).
To find the amperage when HP is shown, this formula is used; I = HP x 746/1.73 x E x %eff x pf.
A standard motor's efficiency between 5 to 100 HP is .84 to .91.
A standard motor's power factor between 10 to 100 HP is .86 to .92.
Amps = 3 x 746 = 2238/1.73 x volts x .84 x .84.
As you can see we can go no further as no voltage
was stated.
The single phase AC motor table in the electrical code states a 7.5 HP motor at 230 volts will draw 40 amps.
To answer this question a voltage must be given.
At least 14 (100% efficient, 1.0pf), likely close to 20 for a real world motor. It depends on the efficiency, load on the motor, and motor power factor.
20
we can use the formula: Ip=KW/3/volts/pf
P=VI P=power V=voltage I=current therefore current drawn is 5000/400=50/4=12.5 amperes
I would guess it would use a third less than a single phase motor. The voltage differences don't save but 3 phase does. A 3 phase motor also starts easier.
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The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
question is incomplete, I think you ask how much current consumed by this motor. for starting this motor we need a star/delta starter and a three phase supply.
we can use the formula: Ip=KW/3/volts/pf
The wiring should allow for 115 amps.
118.72 amp current will be consumedAnswerFirst of all, 70 horsepower is the machines output, not its input, so you cannot calculate its current without knowing its efficiency. Secondly, the current also depends on the type of motor -is it a.c. or d.c? Is it single-phase or three-phase? Without this information, your question cannot be answered.
P=VI P=power V=voltage I=current therefore current drawn is 5000/400=50/4=12.5 amperes
i think the answer is more on economical reasons ( 220v in the phil ).. since Voltage is inversely proportional to current..the higher the voltage, the lower the current..the lower the current, the smaller the electrical cable to use. In short, if we used 220v, electrical cable to be used is much smaller compared to the cable used in 110v..Smaller cable means less price than of the much larger cable.. :))
Probably not. The single phase three horse power motor will be much larger in physical size than its three phase counterpart, and will probably not fit.
Current = Voltage / resistance (more properly impedance) so the current will be 220/55 or 4 amps.
Free
Power in a 3 phase circuit is given by W=√3*V*I*cosφ therefore transposing the formula gives: I=W/√3*V*cosφ where I=current in amps, W=power in watts, V=line voltage, cosφ=power factor (this should be on the motor plate, if not you could use 0.9) Regards ninenix
I would guess it would use a third less than a single phase motor. The voltage differences don't save but 3 phase does. A 3 phase motor also starts easier.
For 1 hp motor, a single phase starter is used. Because a single phase starter gives economy consumption,easy trouble shooting and easy installation when compared to three phase starters and supply....