There are actually three pieces to this puzzle - resistance. And you're missing that one.
If you have to ask this question, you shouldn't be dealing with 11,000V
When sizing power sources, you must match voltage (which you have done) and make sure the supply can supply enough current to the electronics. If your supply is the 800mA, and the equipment using this needs 2500mA, then the power supply is undersized. If the supply is the 2500mA and the user is 800mA, then your power supply is oversized, and will work just fine.
5v
5V
Some simple 3 terminal single chip linear regulators are:+5V - 7805, LM309, LM323-5V - 7905, LM320Some high efficiency single chip switching regulators are: +5V - LM2574-5.0, LT1076-5-5V - LT3015-5Note: always read the datasheet carefully to make sure a part meets the requirements of your application before designing around the part.
Well, trying to clarify your question, if you have a device that normally has a 5V 3.6A adapter, than it likely needs to be able to draw up to 3.6 amps or so for the device to operate normally. So, a 5V 2.6 amp adapter may operate at times, but only when the device is trying to draw less than 2.6 amps. If the device tries to draw more than 2.6 amps than you run the chance of burning out your transformer (the AC adapter), or just not having your device work. Both adapters will put out the 5 volts, but the 2.6 amp adapter will not provide enough current. You can safely use a larger adapter than the 3.6A, as your device will only draw as much current at 5 volts as it needs. On another note, do not try an adapter that puts out the same current but more voltage. Such as 7.5 volts 3.6 amps. This will overdrive your device and potentially burn it out.
assuming 5v steady the 2 amps can be virtual zero by reducing the load present
Depending on the application and other factors, it will TYPICALLY be best to use a transformer. If it's a low current application, you can purchase a small 5V power supply transformer for under $20.00, US.
Output: 5V 1A
13 .5v
Why are you asking someone to do your homework for you? Ask your teacher.
If you have to ask this question, you shouldn't be dealing with 11,000V
AC or DC? AC - use a transformer, DC - forget it - not simple or cheap.
AC or DC? AC - use a transformer, DC - forget it - not simple or cheap.
There's a 12V and a 5V supply. The 5V is for the logic. The 12V supply is for the motor.
When sizing power sources, you must match voltage (which you have done) and make sure the supply can supply enough current to the electronics. If your supply is the 800mA, and the equipment using this needs 2500mA, then the power supply is undersized. If the supply is the 2500mA and the user is 800mA, then your power supply is oversized, and will work just fine.
If a transformer has 20 primary windings and 100 secondary windings, it is a step up transformer. If the secondary voltage is 25v, the primary voltage will be 5v, because the turns ratio is 20 to 100, or 1 to 5.