assuming 5v steady the 2 amps can be virtual zero by reducing the load present
There are 20 million amps or 20,000,000 amps.
no
depends on the amperage. 14 AWG for 15 amps, 12 AWG for 20 amps, 8 AWG for 50 amps.
Yes
The equation that you are looking for is I = E/R. Amps = 120/20 = 6 amps. This is one of the basic equations of Ohm's Law.
There are 20 million amps or 20,000,000 amps.
The wire rating for a # 12 wire is 20 amps. If you are going to continuously load the circuit you need to de-rate the wire by 80%. This brings the current down to 20 x .8 = 16 amps. The wire rating of a # 10 wire is 30 amps. 30 x .8 = 24 amps.
It doesn't. 27 breaks down into 3's, and 20 breaks down to 2's and a 5.
A double breaker is a breaker that has 2 switches on it. One of the switches is 20 amps and the other is 30 amps.
Down with the Scene was created on 2000-06-20.
Down the Elements was created on 2000-04-20.
Jump Down was created on 2000-03-20.
It is 1 to 5 as a ratio in its simplest form
Watts = Amps * Volts Watts = 20 amps * 100 Volts Watts = 2000 2,000 Watts or 2k Watts
Watts = Amps * Volts Watts = 20 amps * 100 Volts Watts = 2000 2,000 Watts or 2k Watts
12-2 (#12-2 conductor) wire doesn't "pull" 20 amps. However, it's ampacity rating is that of 20 amps. #12 copper wire is rated for a total load of 20 amps. So, always use a 20 amp breaker with it.
Because someone changed it and only had a 15 to put in it.