kV is kilovolts, kW is kilowatts, kVA is kilovolt amps and kVAR is kilovolt-amps reactive. A common formula is kVA-squared = kW-squared + kVAR-squared.
To answer this question the voltage of the generator must be given.
Ground clearance132 kv - 6100 mm220 kv - 7015mm400 kv - 8840mm765 kv - 15000mm
KV DRDO is located in C.V.Raman Nagar, Bangalore
The standard voltage for transmission is about 115 to 1,200 kV (long-distance transmission). The extreme high voltages are measured more than 2,000 kV and it is exists between conductor and ground.Answer for UKThe standard transmission voltages in the UK are 400 kV and 275 kV. Primary distribution voltages are 132 kV and 33 kV, and secondary distribution voltages are 11 kV and 400 V. These are all line voltages -i.e. voltages measured between line conductors.
Could be zero, could be 1000 amps. Amps are not the same thing as volts.
Multiply by Amps.
Basically the formula is I = P / V where I = amps, P = power (kV) and V = volts for a single phase 11 kV genset the formula is 11000/400 = 27.5 amps max load. For a 3 PHASE GEN then 11000x0.8/400/3 = 7.3 amps per phase.
220 KV lines used in Kerala have a capacity of 880 Amps
5500 kV is 5.5 Megavolts or 5,500,000 volts. To find the power in watts, multiply the voltage by the current in amps.
This depends on the voltage ... amps = watts / volts 660 W / 110 V = 6 amps 660 W / 220 V = 3 amps 660 W / 330 KV = 2 mA
kV is kilovolts, kW is kilowatts, kVA is kilovolt amps and kVAR is kilovolt-amps reactive. A common formula is kVA-squared = kW-squared + kVAR-squared.
Full load amps for a three phase, 375KVA generator is 375 / (voltage in kV) / sqrt(3).
High power transmission lines carry several hundred amperes up to 2000 amps at voltages up to 500 kV or higher
6500 kW at 240 v would need 6,500,000/240 amps, in other words 27,000 amps. That is not practicable. This amount of power would need to be supplied at a much higher voltage, e.g. 11 kV or 33 kV, 3-phase.
20,000 volts = 20 kv
There are zero watts in 3.5 kilovolts. Watts are the product of Amps x Volts. Without an amperage stated the wattage can not be given.