About 1/2 amp.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
In general Tube Light consumes 0.2 amps in general by 40 Watts.
"Amps" is a steady thing. There's no such thing as "Amps per hour".The current through a 24-watt load is[ 24/the voltage across the load ] Amperes.
A 1450 watt coffee maker will use around 13 amps at 110 volts.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
Amps x volts = watts So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
Amps = Watts/Volts55/12= 4.583333
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
To answer this question the voltage of the bulb is needed.
To find the current in amps for a 50-watt light bulb, you can use the formula ( I = \frac{P}{V} ), where ( I ) is the current in amps, ( P ) is the power in watts, and ( V ) is the voltage in volts. For example, if the bulb operates at 120 volts, the current would be ( \frac{50}{120} ), which equals approximately 0.42 amps. If the bulb operates at a different voltage, simply adjust the voltage in the formula accordingly.
To calculate the amperage drawn by a 300 watt floodlight, you can use the formula: Amps = Watts / Volts. Assuming a standard voltage of 120V for residential lighting, the floodlight would draw approximately 2.5 amps (300W / 120V = 2.5A).
To calculate the amperage, use the formula: Amps = Watts / Volts. In this case, it would be 580 watts / 120 volts = 4.83 amps. Therefore, you would need approximately 4.83 amps for a 580 watt device at 120 volts.