None by itself. Watts are measurement of power, and power is volts times amperes.
Secondly, the 6 volts must be in an electrical circuit (loop) to create current flow (Amps).
Thirdly, the resistance of whatever the 6 volts is powering determines current flow (Amps). So, without knowing the current flow, you cannot calculate power.
Fourth, power (Watts, horsepower, ergs, chevals vapeur, etc) is a measurement taken over a certain time - it is not instantly measureable with an inexpensive meter like a voltmeter or an ammeter (Amp-meter).
None by itself. Watts are measurement of power, and power is volts times amperes.
Secondly, the 6 volts must be in an electrical circuit (loop) to create current flow (Amps).
Thirdly, the resistance of whatever the 6 volts is powering determines current flow (Amps). So, without knowing the current flow, you cannot calculate power.
Fourth, power (Watts, horsepower, ergs, chevals vapeur, etc) is a measurement taken over a certain time - it is not instantly measureable with an inexpensive meter like a voltmeter or an ammeter (Amp-meter).
The formula "P=I * E" where P is Power (Watts), I is Inductance (Amps) and E is Electromotive force (Volts) So in your example I (Amps) = 6 divided by 9, which is 2/3 or 0.666666.... amps. Frager
There are zero watts in 6 volts. Watts is the product of amps x volts. To find watts an amperage has to be stated.
0.25 megawatts is 250,000 watts.
No, the charger has to be equal to or greater than the device it is charging.
45 watts
.0001 watts
100 watt
It generates 12V unless its an older 6V model the correct question is probably how many Watts does it produce
It is: -10v+6v = -4v
yes, you can.
0
Power = V x A = 6 x 0.5 = 3 watts = 3 joules per seconddissipated by the lamp into the surrounding environmentin the form of heat and light.
6 and 18v, respectively.
2u^2-6v-uv
5(6v + 7)(6v - 7)
6v + 7 = -296v = -36v = -6
100wats
132 watts
1540 watts