You have a 3-phase UPS consuming 60kVA at 400V,
So, to determine the current per phase, apply the following formula:
I= S / (U x sqrt[3]) where S is apparent power (in VA)
U is line voltage (in V)
I is current per phase (in A)
thus, this gives I= 60 000/ (400 x sqrt[3])
I=86.6 amps
The ampere is used to measure current, whereas the volt ampere (V.A not va!) is used to measure apparent power. These are two completely different quantities, so you cannot ask how many amperes are there in 60 kV.A any more than asking how many kilometres there are in a litre.
On the other hand, since volt amperes is the product of current and voltage, if you should know the voltage applied to a 60 kV.A load, then you can determine the resulting load current by dividing the apparent power of the load by that voltage. But the load's apparent power and the resulting current remain two completely different quantities.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
The voltage can be either 250000 kilovolts or 240 volts, it can't be both so the question can't be answered. <<>> There are zero amps in 250,000,000 volts. Amps can be found using the following equations. Amps = Volts/Resistance in ohms, Amps = Watts/Volts and Amps = Sq root of Watts/Resistance in ohms.
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
depends what the source voltage isone horsepower equals to 746watts (assuming 100% efficiency)746 watts divided by voltage source equals current (amps)AnswerIn countries, such as the USA, where the horsepower is still used as a means of measuring power, it is always used to measure the output power of a motor.So, in order to determine the current drawn by the motor, you will first need to find out its input power. The input power is the output power divided by the machine's efficiency. Once you know its input power, then you can find its current by dividing the input power by the supply voltage. In practise, you will need to use a wattmeter to determine its input power.
You cannot convert 2.6 kw to amps with that information only. In order to convert watts to amps, you also need to know either current or voltage. This is because watts is volts times amps, and volts is current times resistance
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
500,000 watts/240 volts = 2,083.34 Amps (single phase)
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
75 Amps theoretically Need to know if the generator is 3 phase or single phase.
For a single phase 3 HP motor at 208 volts the amperage is 18.7 amps. For a three phase 3 HP motor at 208 volts the amperage is 10.5 amps. This figure is derived at by taking the full load amps at 230 volts and adding 10%. As the voltage goes down the amperage goes up. For 200 volt motors 15% is added to the FLA of a 230 volt motor.
50 kVA is 16.667 kVA per phase and you divide that by the phase voltage. Current = 16667 / 277 = 60 Amps
160 amps at 12v.
160 amps at 12v.