1 amp
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
Power = Volts x Amps ( P= V*A) Therefore Amps = P/V in this case .5 amps
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
Yes, a 230V bulb can be used on a 120V circuit, but the power output of the bulb will be approximately one quarter. (Half the voltage and half the current) Note, however, that since the bulb will be cooler, the resistance will be slightly less, so power will be somewhat higher than expected, but estimated figure is still one quarter.
The amps (ampiers) decrease when in a series circuit ( with a light bulb)
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
It's 75/120 and the answer is in amps.
You want to know how many amps in that circuit. To do so, divide the Watts by the Volts. in your case it would be 60 watts / 120 volts = 0.5 Amps.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
If the bulb's filament is broken, the whole circuit becomes open. If the bulb is in a series circuit or is the only bulb, the electricity would no longer flow. If the bulb is in a parallel circuit, along with other bulbs, then only the blown bulb would go out, and the other bulbs would still work.
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
Power = Volts x Amps ( P= V*A) Therefore Amps = P/V in this case .5 amps
it would be ok in a circuit which didn't need a light bulb.
Considering an incandescent bulb and using P=VxI P= Power Watts V= Volts I= Current (amperes) I=P/V I=75Watts/120Volts = 0.625 Amperes (A or Amps) Therefore the current through a 75watt bulb that is connected to a 120volt circuit is 0.625 amps.
Efficiency isn't the question. They just do different things. For example, if you look at a typical lighting circuit in a house, all the bulbs on a circuit are in parallel. They each have the same voltage across the bulbs. If you rewired this so that the bulbs were in series then the voltage would be divided across each bulb and if one bulb burned out the others in series would get no current and would not light. If you had two 60Watt bulbs in parallel in your house, each would draw 1/2 Amp. Add another bulb and it would draw 1/2 amp as well, for a total of three 60W bulbs drawing 1.5 amps from the power source. If the same three bulbs were in series there would be 40 Volts across each one with a current of 1/6 amps per bulb. Hence each bulb would be about 1/3 as bright as in the parallel circuit.