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751,5 mm Hg is equal to 0,988 815 8 atmospheres.

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8y ago

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In 150 mm Hg how many atmospheres are there?

There are approximately 0.2 atmospheres in 150 mm Hg. To convert from mm Hg to atmospheres, you can use the conversion factor that 1 atm is equal to 760 mm Hg.


How many atmospheres are equal to 790 mm Hg?

790 mm Hg is equal to approximately 1.04 atmospheres.


How many atmospheres are in 1000 mm Hg?

This value is 1,315 789 atmospheres.


How many atmospheres is 1000 mm Hg?

This value is 1,315 789 atmospheres.


How many atmospheres is 749 mm-Hg equal to?

It is equivalent to 0.986 atmospheres.


How many atmospheres are there in 100 mm Hg?

This value is 0,131 578 9 atmospheres.


What is the conversion factor for atmospheres to mm Hg?

This value is 1 atmosphere=760 mm Hg.


How many atmospheres is 751.5 mmhg?

751 mm col. Hg equal 0,988 157 9 atmosphere.


How many atmospheres are there in 1000mm Hg?

The standard atmosphere, with the symbol atm, is an international reference pressure and used as a unit of pressure. There are 1.31578947 atmospheres in 1000 mm hg.


24.9 inches Hg convert to atmosphere?

To convert 24.9 inches of mercury (Hg) to atmospheres, you can use the conversion factor: 1 atm = 29.92 inHg. Therefore, 24.9 inHg is equal to 24.9/29.92 atmospheres, which is approximately 0.831 atmospheres.


Will measured a gas at 30.0 degrees C and 752.0 mm Hg. What would his measurements be if expressed in Kelvin and atmospheres?

30 degrees C is 303 K. 752 mm Hg is 0.9895 atm.


How do you find the density of two different noble gases helium and radonin a balloon at 21 degree c and 751 mm Hg pressure?

To find the density of helium and radon in a balloon at 21°C and 751 mm Hg, use the ideal gas law, which states (PV = nRT). First, convert the temperature to Kelvin (21°C = 294 K) and the pressure to atmospheres (751 mm Hg ≈ 0.986 atm). Then, calculate the molar volume using (PV = nRT), where (R = 0.0821 , \text{L·atm/(K·mol)}). Finally, divide the molar mass of each gas (helium: 4 g/mol, radon: 222 g/mol) by the molar volume to find their respective densities.