In one mole of helium, there is 6.02 x 10*23 atoms.
In 1 mole of any substance, it contains 6.02 x 10*23 particles of that substance.
This number (6.02 x 10*23) is known as Avogadro's number or Avogadro's constant.
Yes. 16.00g of oxygen is its molar mass, which is the mass of one mole of oxygen. 4.003g is the molar mass of helium, which is also the mass of one mole of helium. One mole of anything is 6.022 x 1023. One mole of oxygen atoms is 6.022 x 1023 atoms of oxygen and one mole of helium atoms is 6.022 x 1023 atoms of helium.
To calculate the mass of silicon in the sample, you would first convert the number of atoms to moles using Avogadro's number. Then, you would calculate the mass of silicon in grams using the molar mass of silicon (28.0855 g/mol). The final mass would depend on the number of atoms in the sample.
To find the number of helium atoms in 542 kg of helium, you need to first calculate the number of moles of helium in 542 kg using the molar mass of helium, which is 4 grams/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of helium to atoms.
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
10g of helium has fewer atoms. This is because the atomic mass of helium is much higher than that of hydrogen, so the same mass of helium contains fewer atoms than the same mass of hydrogen.
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
This number is 12,044 280 171 4.10e23.
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
The number of helium atoms is 6,022 140 857.10e26.
Yes. 16.00g of oxygen is its molar mass, which is the mass of one mole of oxygen. 4.003g is the molar mass of helium, which is also the mass of one mole of helium. One mole of anything is 6.022 x 1023. One mole of oxygen atoms is 6.022 x 1023 atoms of oxygen and one mole of helium atoms is 6.022 x 1023 atoms of helium.
To calculate the mass of silicon in the sample, you would first convert the number of atoms to moles using Avogadro's number. Then, you would calculate the mass of silicon in grams using the molar mass of silicon (28.0855 g/mol). The final mass would depend on the number of atoms in the sample.
To find the number of helium atoms in 542 kg of helium, you need to first calculate the number of moles of helium in 542 kg using the molar mass of helium, which is 4 grams/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of helium to atoms.
To find the number of helium atoms in a helium blimp, you would first need to convert the mass of helium (431 kg) to moles using the molar mass of helium. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of helium atoms.
Atomic Mass of helium is 4.002602
To find the number of helium atoms, we need to convert the mass of helium to moles and then use Avogadro's number to convert moles to atoms. The molar mass of helium is 4 g/mol. First, convert 590 kg to grams (590,000 g). Then, divide by the molar mass of helium to find moles, and finally multiply by Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.
No, a mole of carbon atoms has the same number of atoms as a mole of helium atoms (Avogadro's number, which is about 6.022 x 10^23 atoms). The difference lies in their atomic masses, as carbon atoms are heavier than helium atoms.
If the chemical composition of the sample is known, then the answer is yes. However, equal masses of platinum and magnesium, for example, contain quite different numbers of atoms, because the atomic mass of platinum is much higher than that of magnesium.