The answer is 8,1547.10e25.
There are approximately 1.19 x 10^28 atoms of U-234 in 1000 kg of natural uranium.
The answer is 6,2729.10e+26 carbon atoms.
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
First calculate the moles of sodium moles = 500 g/ 23 = 21.739 ... Remember the Avogadro Number. 6.022 x 10^(23) is the number of atoms in one mole Hence , multiplying 6.022 x 10^(23) X 21.739... = 1.309 x 10^(25) atoms in 0.5 kg of sodium .
To find the number of chromium atoms in 147.4 kg of chromium, we first need to convert the mass to moles using the molar mass of chromium (51.996 g/mol). Then, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms. The calculation would be (147.4 kg / 51.996 g/mol) * 6.022 x 10^23 atoms/mol.
The answer is 800,424.1026 atoms.
1 mole of helium (or 4 g or 0.004 kg) will have 6 x 1023 atoms. So, 544 kg will have 8.16 x 1028 atoms.
To find the number of helium atoms in a helium blimp, you would first need to convert the mass of helium (431 kg) to moles using the molar mass of helium. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to calculate the number of helium atoms.
To find the number of helium atoms in the blimp, you first calculate the number of moles of helium in 533 kg of helium using the molar mass of helium. Then, you use Avogadro's number (6.022 x 10^23) to convert moles to atoms. The final answer will give you the number of helium atoms in the blimp.
To find the number of helium atoms, we need to convert the mass of helium to moles and then use Avogadro's number to convert moles to atoms. The molar mass of helium is 4 g/mol. First, convert 590 kg to grams (590,000 g). Then, divide by the molar mass of helium to find moles, and finally multiply by Avogadro's number (6.022 x 10^23 atoms/mol) to get the number of atoms.
542 kg = 1,195 pounds
520 kg = 5.20 X 105 grams. The gram atomic mass of helium is 4.0026; therefore the number of moles of helium in 520 kg is (5.20/4.0026) X 105 or 1.30 X 105. Multiplying this number by Avogadro's Number, 6.022 X 1023, yields the number of atoms, which is about 7.82 X 1028, to the justified number of significant digits.
246kg = 542.34 pounds.
The answer is 50,38349e+23 atoms.
to lift 1 kg or 2 pounds you need 0.16 kg of helium so for 2000 pounds you need 160 kg of helium or 320 pounds at 1 atmosphere
12,4439 kg of gold contain 63,177 moles.
There are approximately 1.19 x 10^28 atoms of U-234 in 1000 kg of natural uranium.