The answer is 6,2729.10e+26 carbon atoms.
To determine the number of half-lives that have elapsed, we first find the total number of atoms in the sample, which is 500 (125 + 375). The starting atom would have been from 250 atoms of C-14. To find the number of half-lives elapsed, we divide the total number of atoms by the starting amount (500/250). This gives us 2 half-lives that have elapsed.
The general formula of linear alkanes is CnH2n+2. If an alkane with 125 carbons exist (I don't know) the chemical formula will be C125H252 and the name pentacosehectane.
There will be 125 atoms of Na24 remaining in the sample after 45 hours. This calculation is based on the fact that after 3 half-lives (45 hours/15 hours per half-life), the original 1000 atoms would have reduced by a factor of 2 three times, resulting in 1000/2/2/2 = 125 atoms remaining.
Based on the half-life of Na-24, after 1 half-life (15 hours), there would be 500 atoms remaining. After 2 half-lives (30 hours), there would be 250 atoms remaining. After 3 half-lives (45 hours), there would be 125 atoms remaining in the sample.
To find the number of moles of nickel atoms in 125 g of nickel, divide the given mass by the molar mass of nickel. The molar mass of nickel is approximately 58.69 g/mol. Therefore, 125 g Ni / 58.69 g/mol = ~2.13 moles of Ni atoms.
To determine the number of half-lives that have elapsed, we first find the total number of atoms in the sample, which is 500 (125 + 375). The starting atom would have been from 250 atoms of C-14. To find the number of half-lives elapsed, we divide the total number of atoms by the starting amount (500/250). This gives us 2 half-lives that have elapsed.
The general formula of linear alkanes is CnH2n+2. If an alkane with 125 carbons exist (I don't know) the chemical formula will be C125H252 and the name pentacosehectane.
We have now way of knowing unless we know the initial number of C-14
There will be 125 atoms of Na24 remaining in the sample after 45 hours. This calculation is based on the fact that after 3 half-lives (45 hours/15 hours per half-life), the original 1000 atoms would have reduced by a factor of 2 three times, resulting in 1000/2/2/2 = 125 atoms remaining.
Based on the half-life of Na-24, after 1 half-life (15 hours), there would be 500 atoms remaining. After 2 half-lives (30 hours), there would be 250 atoms remaining. After 3 half-lives (45 hours), there would be 125 atoms remaining in the sample.
To find the number of moles of nickel atoms in 125 g of nickel, divide the given mass by the molar mass of nickel. The molar mass of nickel is approximately 58.69 g/mol. Therefore, 125 g Ni / 58.69 g/mol = ~2.13 moles of Ni atoms.
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
125
125
1.6 g/ml
We are as backward as 125 years ago.
That is 125 ml.