If you think to a simple binary bromide as NaBr: 166,57.10e23 atoms.
Magnesium bromide IS a molecule, or more correctly, it is a formula unit. So, magnesium bromide doesn't HAVE any molecules. One formula unit of magnesium bromide has THREE ATOMS, and they are 1 magnesium atom and 2 bromine atoms (MgBr2).
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
substance
A metal bromide contain the ion Br-; sodium bromide is an example.
If you think to a simple binary bromide as NaBr: 166,57.10e23 atoms.
Ammonium bromide - NH4Br - contain 6 atoms.
1
Magnesium bromide IS a molecule, or more correctly, it is a formula unit. So, magnesium bromide doesn't HAVE any molecules. One formula unit of magnesium bromide has THREE ATOMS, and they are 1 magnesium atom and 2 bromine atoms (MgBr2).
Any molecular formula will tell you how many atoms are in it. I don't want to just give you the answer so let's use another atom...C6H12O6. Your basic monosaccharide. It has... 6 carbon atoms 12 hydrogen 6 oxygen Add 'em up and you get 24 atoms. An atom that doesn't have a number behind it has only one example of it in each molecule...CH4 has one carbon and four hydrogens.
one mole of a substance is described as 6.02x1023 atoms of a substance so if one mole of bromide gas contains 6.02x1023 atoms then bromide gas will contain one mole. your question is a trick question as the gas is stated as containg one mole there fore it contains one mole of bromide atoms
Formula: Al
Potassium bromide has the formula KBr and it contains one atom of Potassium (K) and one atom of Bromine (Br).
10
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
The compound sodium bromide is formed by the formation of ionic bonds between sodium and bromide ions.
to cut sheet or aluinium metal