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The formula for iron(II) bromide is FeBr2.
Fe+2 Br-1 = The ions and their chargesFe+2 Br-1 Br-1 = The ions have to add up to zero, so two -1 bromine ions cancel out one +2 iron ionFeBr2 = simplification and final answer
if iron has an oxidation state of +2 K2(CO3) + FeBr2 ---> KBr + FeCO3 if iron has an oxidation state of +3 3K2(CO3) + 2FeBr3 ----> 6KBr + Fe2(CO3)3
The chemical formula for Iron(III) bromide is FeBr3. It consists of one iron atom bonded to three bromine atoms.
chromium (III) bromide calcium chloride OR iron (III) oxide aluminum chloride
The formula for iron(II) bromide is FeBr2.
One formula unit of FeBr2 contains one iron atom.
The correct formula for iron(ll) bromide is FeBr2.
The ionic compound name for FeBr2 is iron(II) bromide.
* iron (II) bromide * iron bromide * iron dibromide
FeBr2 is Iron II Bromide
FeBr2
It is Iron-(II)-bromine
Iron bromide is composed of iron (Fe) and bromine (Br) atoms. It can exist in different forms, such as FeBr2 (iron(II) bromide) or FeBr3 (iron(III) bromide), depending on the oxidation state of the iron atom.
FeBr3
It is not an element, it's a compound. It would be called iron (II) bromide in the IUPAC system, or ferrous bromide in the antiquated pre-IUPAC nomenclature.
There re two bromides of iron, iron(II) bromide, FeBr2, and iron(III) bromide FeBr3