There is apporximately 0.07 mol of He in .268g, which is approximately 4.21x10^-23 atoms.
1.3 mol
48,177 134 32.1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
1.13x10^23
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
There are 1.204 x 1023 atoms in .200 mol of Pb.
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
There is apporximately 0.07 mol of He in .268g, which is approximately 4.21x10^-23 atoms.
1.3 mol
The answer is 18,061.1023 atoms.
481,7713432.1023 atoms
48,177 134 32.1023 atoms
Avagadro's number = 6.022 × 1023 atoms/mol0.5 mol × (6.022 × 1023) atoms/mol = 3.011 ×1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.