The burning of glucose is the following:C6H12O6(s) + 6O2(g) =6CO2(g) + 6H2O(g).
This is composition. When it is "+O2" it means that it is burned in air.
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
2(c3h8o)+9o2 => 8h2o+6co2
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3
Complete combustion : 2C3H8O + 9O2 --> 6CO2 + 8H2O Incomplete combustion : C3H8O + 3O2 --> 3CO + 4H2O
The combustion of isopropyl alcohol.
The burning of glucose is the following:C6H12O6(s) + 6O2(g) =6CO2(g) + 6H2O(g).
This is composition. When it is "+O2" it means that it is burned in air.
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
With combustion equations always balance the O2 last. C10H8 + 12O2 >> 10CO2 + 4H2O
2(c3h8o)+9o2 => 8h2o+6co2
No, the balanced equation is 6Ca + 3O2 ---> 6CaO. The product, calcium oxide, is CaO and not CaO2.
C6H12 (aq) + 9O2 (g) ==> 6CO2 (g) + 6H2O
2Fe(ClO3)3 ->2FeCl3 + 9O2
C6H12(l)+9O2(g)---->6CO2(g)+6H2O(l) apex
C8H16 + 12O2 ------> 8CO2 + 8H2O