first find the number of moles of nitrogen in 1.00g than times by 6.02*10^23
n(N)=1/14 * 6.02*10^23
=4.2*10^22 atoms
about 24.99% nitrogen is present in ammonium chloride........
The gram atom mass of 5 nitrogen atoms is 5 times the gram atom mass for a single nitrogen atoms, which can be found, in a periodic table or other reference, to be 14.007. Therefore the gram atom mass of 5 N atoms is 5 X 14.007 = 70.035. 23.4 % = 0.234. From the problem statement, the unknown molar mass M of the substance obeys the relationship 0.234 M = 70.035, or M = 299, to the justified number of significant digits.
If all the magnesium atoms are going to react, they will each need to combine with two oxygen atoms to form magnesium oxide. Therefore, for 100 magnesium atoms, you would need 200 oxygen atoms, which is equivalent to 100 oxygen molecules.
If there are 100 types of atoms, then the number of different compounds that could form by pairing any two atoms is calculated by using the combination formula: C(100, 2) = 100! / [(100-2)! * 2!] = 4950 different compounds.
There are 0 hydrogen atoms. I m not 100% sure but maybe 90% sure =)
Two atoms of nitrogen form the gaseous, natural state, of nitrogen. 10.62 grams N2 (1 mole N2/28.02 grams)(6.022 X 10^23/1 mole N2)(1 mole N2 atoms/6.022 X 10^23) 0.3790 mole of gaseous nitrogen atoms ------------------------------------------------------ * as you may see, Avogadro's number is over itself as a form of one and is a superfluous step put there for formality's sake
about 24.99% nitrogen is present in ammonium chloride........
HNNH has the shorter nitrogen-nitrogen bond because it has a triple bond between the nitrogen atoms, which is shorter and stronger than the single bond in H2NNH2.
Protein, Carbon, and nitrogen. I'm 100% sure about that!
The gram atom mass of 5 nitrogen atoms is 5 times the gram atom mass for a single nitrogen atoms, which can be found, in a periodic table or other reference, to be 14.007. Therefore the gram atom mass of 5 N atoms is 5 X 14.007 = 70.035. 23.4 % = 0.234. From the problem statement, the unknown molar mass M of the substance obeys the relationship 0.234 M = 70.035, or M = 299, to the justified number of significant digits.
The number of atoms cannot be estimated to that degree of accuracy.
Assuming the urea has the normal grade of 46% nitrogen, it has a total of 100 pounds, or units, of nitrogen.
To find the number of atoms in 100 grams of gold, you would first calculate the number of moles using the molar mass of gold (197 grams/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, approximately 3.01 x 10^23 atoms of gold are present in 100 grams.
No. 100 lead atoms are several times heavier than 100 aluminum atoms.
100%
The length of nitrogen-to-nitrogen bond is approx. 100 pm.
If all the magnesium atoms are going to react, they will each need to combine with two oxygen atoms to form magnesium oxide. Therefore, for 100 magnesium atoms, you would need 200 oxygen atoms, which is equivalent to 100 oxygen molecules.