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Two atoms of nitrogen form the gaseous, natural state, of nitrogen.
10.62 grams N2 (1 mole N2/28.02 grams)(6.022 X 10^23/1 mole N2)(1 mole N2 atoms/6.022 X 10^23)
0.3790 mole of gaseous nitrogen atoms
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* as you may see, Avogadro's number is over itself as a form of one and is a superfluous step put there for formality's sake
What else can I help you with?
How many moles of ammonia gas are produced by the reaction of 3 mole of nitrogen gas with excess hydrogen gas N2 H2 ---- NH3?
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
How many moles of nitrogen are there in 3 moles of ammonium nitrate?
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
How many moles are present in 10.0 L of nitrogen gas at STP?
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
How many moles of nitrogen gas are there in 35.7 gm of nitrogen gas?
To calculate the number of moles of nitrogen gas in 35.7 g, you can use the molar mass of nitrogen, which is 28 g/mol. First, divide the given mass by the molar mass to find the number of moles: ( \frac{35.7 , \text{g}}{28 , \text{g/mol}} \approx 1.275 , \text{mol}). Therefore, there are approximately 1.275 moles of nitrogen gas in 35.7 g.
How many moles of nitrogen are contained in 18.65 L at STP?
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
How many moles of ammonia gas are produced by the reaction of 3 mole of nitrogen gas with excess hydrogen gas N2 H2 ---- NH3?
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
How many moles of nitrogen are there in 3 moles of ammonium nitrate?
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
How many moles are present in 10.0 L of nitrogen gas at STP?
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
What are the no of moles in 100gm of nitrogen gas?
3.6
How many moles of electrons are required to reduce one mole of nitrogen gas N2 to two moles of nitrogen ions N3-?
Three moles of electrons are required to reduce one mole of nitrogen gas N2 to two moles of nitrogen ions N3-. This is because each nitrogen molecule N2 gains 3 electrons to form two nitrogen ions N3-.
How many moles of nitrogen gas are there in 35.7 gm of nitrogen gas?
To calculate the number of moles of nitrogen gas in 35.7 g, you can use the molar mass of nitrogen, which is 28 g/mol. First, divide the given mass by the molar mass to find the number of moles: ( \frac{35.7 , \text{g}}{28 , \text{g/mol}} \approx 1.275 , \text{mol}). Therefore, there are approximately 1.275 moles of nitrogen gas in 35.7 g.
How many nitrogen atoms are in .25 mole of nitrogen gas?
There are 1 mole of nitrogen gas molecules contain 2 nitrogen atoms. Therefore, 0.25 mole of nitrogen gas would contain 0.25 * 2 = 0.5 moles of nitrogen atoms.
How many nitrogen molecules are in 12.88g of nitrogen gas?
To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.
How many molecules are in 140gm of nitrogen gas?
To determine the number of molecules in 140g of nitrogen gas, you first need to convert the mass of nitrogen gas to moles using its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol. Once you have the number of moles of nitrogen gas, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules present in 140g of nitrogen gas.
How many moles of nitrogen are contained in 18.65 L at STP?
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
Can you provide some gas stoichiometry practice problems for me to work on?
Here are some gas stoichiometry practice problems for you to work on: How many liters of oxygen gas are needed to completely react with 5.0 liters of hydrogen gas to produce water vapor? If 2.0 moles of methane gas react with excess oxygen gas, how many moles of carbon dioxide gas will be produced? A reaction produces 4.0 liters of nitrogen gas. If the reaction is 80 efficient, how many liters of nitrogen gas would be produced if the reaction was 100 efficient? These problems will help you practice applying gas stoichiometry concepts.
How many moles of nitrogen and oxygen are in a cubic foot?
To determine the number of moles of nitrogen and oxygen in a given volume like a cubic foot, you would first need to know the pressure and temperature of the gas. Then you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. So without knowing the pressure and temperature, it is not possible to determine the number of moles of nitrogen and oxygen in a cubic foot.
