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PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.

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Wiki User

8y ago
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Wiki User

8y ago

18,65 L nitrogen is equivalent to 0,832 mol at 0 oC.

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Wiki User

8y ago

At STP 1 mole of any gas is contained in 22.4 L. So in 18.65 L, there will be 0.83 moles of nitrogen.

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Anthony Caddy

Lvl 3
2y ago

0.832 moles

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Q: How many moles of nitrogen are contained in 18.65 L at STP?
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