The answer is 0,1 mol.
To find the weight of 500 moles of CuBr, you first need to determine the molar mass of CuBr which is 159.43 g/mol. Then, you can calculate the weight by multiplying the number of moles by the molar mass: 500 moles * 159.43 g/mol = 79,715 g.
The answer is 1,5 moles.
3,6 x 1023 molecules of oxygen gas O2 are equivalent to approx. 0,6 moles.
You have to say which chemical you have 500 liters of. Moles are not a unit of volume, they refer to a specific number (Avogadro's number) of molecules, and different substances have different molecular sizes.
To find the number of moles in 500 grams of radium (Ra), you need to divide the given mass by the molar mass of radium. The molar mass of radium is approximately 226 grams/mol, so 500 grams of radium is equal to 500 grams / 226 grams/mol ≈ 2.21 moles of radium.
The answer is 0,1 mol.
1 mole of HCl reacts with 1 mole of KOH. Therefore, 0.5 moles of KOH (500 mL = 0.5 L) are needed to neutralize 0.5 moles of HCl.
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.
To find the weight of 500 moles of CuBr, you first need to determine the molar mass of CuBr which is 159.43 g/mol. Then, you can calculate the weight by multiplying the number of moles by the molar mass: 500 moles * 159.43 g/mol = 79,715 g.
The molar mass of ammonia is 17,031 g.17,031 g NH3-------------------1 mol500 g NH3-------------------------xx= 500/17,031 = 29,36 moles
The answer is 1,5 moles.
Balanced equation first. 2H2 + O2 -> 2H2O 250 moles O2 (2 mole H2O/1 mole O2) = 500 mole H2O produced now, since I am forgetful, I will use density formula at 25 C Density = grams/milliliters 500 moles H2O (18.016 grams/1 mole H2O) = 9008 grams H2O 0.9982 g/ml = 9008 grams/milliliters 9024.24 milliliters H2O this is...... 9.02 liters of water produced in this reaction.
Assuming each Tums tablet contains 500 mg of calcium carbonate, there is a total of 6 grams of calcium carbonate in one roll of Tums (12 tablets x 500 mg). To calculate the number of moles, divide the mass by the molar mass of calcium carbonate (100.09 g/mol), yielding around 0.06 moles of calcium carbonate in one roll of Tums.
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, plug in the values: M = 2.5 moles / 0.5 L = 5 M. Hence, the molarity of the solution is 5 M.
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
3,6 x 1023 molecules of oxygen gas O2 are equivalent to approx. 0,6 moles.