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Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP.

So, moles of 10L = 10/22.4 moles

= 0.4464 moles

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How many no of moles in 100 gm of nitrogen gas?

Two atoms of nitrogen form the gaseous, natural state, of nitrogen. 10.62 grams N2 (1 mole N2/28.02 grams)(6.022 X 10^23/1 mole N2)(1 mole N2 atoms/6.022 X 10^23) 0.3790 mole of gaseous nitrogen atoms ------------------------------------------------------ * as you may see, Avogadro's number is over itself as a form of one and is a superfluous step put there for formality's sake


What is the percent and the weight of nitrogen in 8.941 mol of ammonium sulfide?

Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms. One mole of (NH4)2S contains 2 moles of nitrogen. In 8.941 mol of (NH4)2S, there are 8.941 x 2 = 17.882 mol of nitrogen. To find the percent of nitrogen by weight, you would compare the molar mass of nitrogen to the molar mass of the compound and then multiply by 100.


How many moles of phosphorus atoms are in 100 grams of P4S10?

To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.


Which would lower the freezing point more 100 moles of sugar or 100 moles of NaCl?

100 moles of NaCl would lower the freezing point more than 100 moles of sugar. This is because NaCl dissociates into more particles in solution compared to sugar, resulting in a greater depression of the freezing point due to colligative properties.


100 grams of ammonia equals how many moles?

For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3

Related Questions

How many moles of Al2S3 are in 100 g of Al2S3?

100/150.158 is 0.666 moles


How many moles of each element are present in a 100 g sample of deoxyribose?

Deoxyribose has the chemical formula C₅H₁₀O₃. In a 100 g sample of deoxyribose, the number of moles can be calculated using its molar mass, which is approximately 134.13 g/mol. Thus, the number of moles of deoxyribose is about 0.746 moles. Consequently, there would be 0.746 moles of carbon, 1.492 moles of hydrogen, and 0.746 moles of oxygen in the sample.


How many moles of water are there in 1.792 L?

95,474 moles


How many moles of hydrogen are in 100 moles of H2O?

200. The formula is for every 1 Oxygen atom, 2 Hydrogen atoms must be present in water. Otherwise you would produce H2O2 (you cannot make it HO because it is never found in molecules on it's own) which is bleach.


How many no of moles in 100 gm of nitrogen gas?

Two atoms of nitrogen form the gaseous, natural state, of nitrogen. 10.62 grams N2 (1 mole N2/28.02 grams)(6.022 X 10^23/1 mole N2)(1 mole N2 atoms/6.022 X 10^23) 0.3790 mole of gaseous nitrogen atoms ------------------------------------------------------ * as you may see, Avogadro's number is over itself as a form of one and is a superfluous step put there for formality's sake


How many moles are present in a sample of HCl with a mass of 3.65?

0.1mol


What is the percent of nitrogen in 4.444 moles of ammonium sulfide?

It is important to know that the percent of nitrogen in 4.444 moles of ammonium sulfide is the same as the percent of nitrogen in 454 grams or 4843 moles or 96 kg, etc. Remember the law of definite proportions - chemical compounds always contain the same proportion of elements by mass. Perhaps you were asking how much nitrogen is in 4.444 moles of ammonium sulfide given the percent of nitrogen in any given mass. So we'll do that too: find the percent of nitrogen in any given sample and apply it specifically to 4.444 moles.Before we go directly to the 4.444 moles, we have to figure out how much nitrogen is in any amount of ammonium sulfide by percent. To do this, we need the atomic weights of the elements and add them up to find the total molar mass of the compound.Ammonium sulfide = (NH4)2SNitrogen = 14.0 grams × 2 = 28.0 gramsHydrogen = 1.01 grams × 8 = 8.08 gramsSulfur = 32.1 grams------------------------------------------------------Ammonium sulfide = 68.2 gramsNow we take the mass of nitrogen and divide it by the total mass to get our percent.Nitrogen ÷ Ammonium sulfide = % Nitrogen28.0 grams ÷ 68.2 grams = 0.411 = 41.1% Nitrogen in Ammonium sulfideSince we know that in any amount of Ammonium sulfide contains 41.1% of Nitrogen, we can apply it to the mass given.41.1% of 4.444 moles = .411 × 4.444 = 1.83 moles of Nitrogen in 4.444 moles Ammonium sulfide


What is the amount of nitrogen in ammonium chloride?

about 24.99% nitrogen is present in ammonium chloride........


How many grams of argon are in 100 mole?

To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.


What is the percent and the weight of nitrogen in 8.941 mol of ammonium sulfide?

Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms. One mole of (NH4)2S contains 2 moles of nitrogen. In 8.941 mol of (NH4)2S, there are 8.941 x 2 = 17.882 mol of nitrogen. To find the percent of nitrogen by weight, you would compare the molar mass of nitrogen to the molar mass of the compound and then multiply by 100.


What are the elements present in carbohydrates?

Protein, Carbon, and nitrogen. I'm 100% sure about that!


How many moles of sodium borohydride are used in 100 mg?

To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.