3.6
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
Three moles of electrons are required to reduce one mole of nitrogen gas N2 to two moles of nitrogen ions N3-. This is because each nitrogen molecule N2 gains 3 electrons to form two nitrogen ions N3-.
To calculate the number of moles of nitrogen gas in 35.7 g, you can use the molar mass of nitrogen, which is 28 g/mol. First, divide the given mass by the molar mass to find the number of moles: ( \frac{35.7 , \text{g}}{28 , \text{g/mol}} \approx 1.275 , \text{mol}). Therefore, there are approximately 1.275 moles of nitrogen gas in 35.7 g.
To determine the number of molecules in 140g of nitrogen gas, you first need to convert the mass of nitrogen gas to moles using its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol. Once you have the number of moles of nitrogen gas, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules present in 140g of nitrogen gas.
The number of moles in 11.2 liters of nitrogen gas (N2) can be calculated using the ideal gas law. Since you have two nitrogen atoms per molecule of N2, you would need to convert the volume of gas to moles using the ideal gas constant.
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.
There are 1 mole of nitrogen gas molecules contain 2 nitrogen atoms. Therefore, 0.25 mole of nitrogen gas would contain 0.25 * 2 = 0.5 moles of nitrogen atoms.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2
4.561 / 28 = 0.163 moles of nitrogen.