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Informational redundancy is the number of bits that it takes to transmit the desired message minus the actual number of bits that the message contains. In other words, it is the extra bandwidth required to send a message.
In order to know how many bits/second there are in 1 frame/second, you need to know how many bits are in that frame. In a typical asychronous serial protocol with 8 bits per frame, the bit rate would be 0.125 bits/second. If you are talking the IP network layer of TCP/IP, then the frame size is very dependent on the underlying message payload and headers.The original question, by the way, is invalid. Its asks "how many bits does...", but it should have asked "how manys bits per second does...".
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In linear block codes we use individual registers seperately for message bits and for parity bits while transmitting where in case of convolutional codes we use only one register and here the left most bit is the message bit and remaining are parity bits
19,200 bits.
16 bits
96,000 bits However, in Kilobytes (KB), there would be 98304 bits.
one kilobit or k is 1024 bits
The generator matrix is made out of that code word and all the possibilities for the code words. The number of rows of the generator matrix are the number of message bits and the number of columns are equal to the total number of bits i.e parity bits + message bits. The only necessary condition is that each row of generator matrix is linearly independent of the other row.
1,374,389,534,720 bits